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How slicing in Python works
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Problem
How does Python's slice notation work? That is: when I write code like
See Why are slice and range upper-bound exclusive? to learn why
See Make a new list containing every Nth item in the original list for
See How does assignment work with list slices? to learn what
a[x:y:z], a[:], a[::2] etc., how can I understand which elements end up in the slice?See Why are slice and range upper-bound exclusive? to learn why
xs[0:2] == [xs[0], xs[1]], not [..., xs[2]].See Make a new list containing every Nth item in the original list for
xs[::N].See How does assignment work with list slices? to learn what
xs[0:2] = ["a", "b"] does.Solution
The syntax is:
There is also the
The key point to remember is that the
The other feature is that
Similarly,
Python is kind to the programmer if there are fewer items than you ask for. For example, if you ask for
Relationship with the
A
is equivalent to:
Slice objects also behave slightly differently depending on the number of arguments, similar to
To skip specifying a given argument, one might use
While the
a[start:stop] # items start through stop-1
a[start:] # items start through the rest of the array
a[:stop] # items from the beginning through stop-1
a[:] # a copy of the whole arrayThere is also the
step value, which can be used with any of the above:a[start:stop:step] # start through not past stop, by stepThe key point to remember is that the
:stop value represents the first value that is not in the selected slice. So, the difference between stop and start is the number of elements selected (if step is 1, the default).The other feature is that
start or stop may be a negative number, which means it counts from the end of the array instead of the beginning. So:a[-1] # last item in the array
a[-2:] # last two items in the array
a[:-2] # everything except the last two itemsSimilarly,
step may be a negative number:a[::-1] # all items in the array, reversed
a[1::-1] # the first two items, reversed
a[:-3:-1] # the last two items, reversed
a[-3::-1] # everything except the last two items, reversedPython is kind to the programmer if there are fewer items than you ask for. For example, if you ask for
a[:-2] and a only contains one element, you get an empty list instead of an error. Sometimes you would prefer the error, so you have to be aware that this may happen.Relationship with the
slice objectA
slice object can represent a slicing operation, i.e.:a[start:stop:step]is equivalent to:
a[slice(start, stop, step)]Slice objects also behave slightly differently depending on the number of arguments, similar to
range(), i.e. both slice(stop) and slice(start, stop[, step]) are supported.To skip specifying a given argument, one might use
None, so that e.g. a[start:] is equivalent to a[slice(start, None)] or a[::-1] is equivalent to a[slice(None, None, -1)].While the
:-based notation is very helpful for simple slicing, the explicit use of slice() objects simplifies the programmatic generation of slicing.Code Snippets
a[start:stop] # items start through stop-1
a[start:] # items start through the rest of the array
a[:stop] # items from the beginning through stop-1
a[:] # a copy of the whole arraya[start:stop:step] # start through not past stop, by stepa[-1] # last item in the array
a[-2:] # last two items in the array
a[:-2] # everything except the last two itemsa[::-1] # all items in the array, reversed
a[1::-1] # the first two items, reversed
a[:-3:-1] # the last two items, reversed
a[-3::-1] # everything except the last two items, reverseda[start:stop:step]Context
Stack Overflow Q#509211, score: 6656
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