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How do I remove the first item from a list?

Submitted by: @import:stackoverflow-api··
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howlisttheitemremovefirstfrom

Problem

How do I remove the first item from a list?

[0, 1, 2, 3]   →   [1, 2, 3]

Solution

You can find a short collection of useful list functions here.

list.pop(index)

>>> l = ['a', 'b', 'c', 'd']
>>> l.pop(0)
'a'
>>> l
['b', 'c', 'd']
>>>


del list[index]

>>> l = ['a', 'b', 'c', 'd']
>>> del l[0]
>>> l
['b', 'c', 'd']
>>>


These both modify your original list.

Others have suggested using slicing:

  • Copies the list



  • Can return a subset



Also, if you are performing many pop(0), you should look at collections.deque

from collections import deque
>>> l = deque(['a', 'b', 'c', 'd'])
>>> l.popleft()
'a'
>>> l
deque(['b', 'c', 'd'])


  • Provides higher performance popping from left end of the list

Code Snippets

>>> l = ['a', 'b', 'c', 'd']
>>> l.pop(0)
'a'
>>> l
['b', 'c', 'd']
>>>
>>> l = ['a', 'b', 'c', 'd']
>>> del l[0]
>>> l
['b', 'c', 'd']
>>>
from collections import deque
>>> l = deque(['a', 'b', 'c', 'd'])
>>> l.popleft()
'a'
>>> l
deque(['b', 'c', 'd'])

Context

Stack Overflow Q#4426663, score: 1697

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