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What is a clean "pythonic" way to implement multiple constructors?
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Problem
I can't find a definitive answer for this. As far as I know, you can't have multiple
Suppose I have a class called
I can think of only one way to do this, but this seems clunky:
What do you say? Is there another way?
__init__ functions in a Python class. So how do I solve this problem?Suppose I have a class called
Cheese with the number_of_holes property. How can I have two ways of creating cheese objects...- One that takes a number of holes like this:
parmesan = Cheese(num_holes=15).
- And one that takes no arguments and just randomizes the
number_of_holesproperty:gouda = Cheese().
I can think of only one way to do this, but this seems clunky:
class Cheese:
def __init__(self, num_holes=0):
if num_holes == 0:
# Randomize number_of_holes
else:
number_of_holes = num_holesWhat do you say? Is there another way?
Solution
Actually
Now if you want complete freedom of adding more parameters:
To better explain the concept of
http://docs.python.org/reference/expressions.html#calls
None is much better for "magic" values:class Cheese:
def __init__(self, num_holes=None):
if num_holes is None:
...Now if you want complete freedom of adding more parameters:
class Cheese:
def __init__(self, *args, **kwargs):
# args -- tuple of anonymous arguments
# kwargs -- dictionary of named arguments
self.num_holes = kwargs.get('num_holes', random_holes())To better explain the concept of
*args and **kwargs (you can actually change these names):def f(*args, **kwargs):
print('args:', args, 'kwargs:', kwargs)
>>> f('a')
args: ('a',) kwargs: {}
>>> f(ar='a')
args: () kwargs: {'ar': 'a'}
>>> f(1,2,param=3)
args: (1, 2) kwargs: {'param': 3}http://docs.python.org/reference/expressions.html#calls
Code Snippets
class Cheese:
def __init__(self, num_holes=None):
if num_holes is None:
...class Cheese:
def __init__(self, *args, **kwargs):
# args -- tuple of anonymous arguments
# kwargs -- dictionary of named arguments
self.num_holes = kwargs.get('num_holes', random_holes())def f(*args, **kwargs):
print('args:', args, 'kwargs:', kwargs)
>>> f('a')
args: ('a',) kwargs: {}
>>> f(ar='a')
args: () kwargs: {'ar': 'a'}
>>> f(1,2,param=3)
args: (1, 2) kwargs: {'param': 3}Context
Stack Overflow Q#682504, score: 976
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