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How do I do a case-insensitive string comparison?
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howinsensitivecasestringcomparison
Problem
How can I compare strings in a case insensitive way in Python?
I would like to encapsulate comparison of a regular strings to a repository string, using simple and Pythonic code. I also would like to have ability to look up values in a dict hashed by strings using regular python strings.
I would like to encapsulate comparison of a regular strings to a repository string, using simple and Pythonic code. I also would like to have ability to look up values in a dict hashed by strings using regular python strings.
Solution
Assuming ASCII strings:
As of Python 3.3, casefold() is a better alternative:
If you want a more comprehensive solution that handles more complex unicode comparisons, see other answers.
string1 = 'Hello'
string2 = 'hello'
if string1.lower() == string2.lower():
print("The strings are the same (case insensitive)")
else:
print("The strings are NOT the same (case insensitive)")As of Python 3.3, casefold() is a better alternative:
string1 = 'Hello'
string2 = 'hello'
if string1.casefold() == string2.casefold():
print("The strings are the same (case insensitive)")
else:
print("The strings are NOT the same (case insensitive)")If you want a more comprehensive solution that handles more complex unicode comparisons, see other answers.
Code Snippets
string1 = 'Hello'
string2 = 'hello'
if string1.lower() == string2.lower():
print("The strings are the same (case insensitive)")
else:
print("The strings are NOT the same (case insensitive)")string1 = 'Hello'
string2 = 'hello'
if string1.casefold() == string2.casefold():
print("The strings are the same (case insensitive)")
else:
print("The strings are NOT the same (case insensitive)")Context
Stack Overflow Q#319426, score: 827
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