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How can I check if a string represents an int, without using try/except?
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representshowintexceptusingtrycancheckwithoutstring
Problem
Is there any way to tell whether a string represents an integer (e.g.,
'3', '-17' but not '3.14' or 'asfasfas') Without using a try/except mechanism?is_int('3.14') == False
is_int('-7') == True
Solution
If you're really just annoyed at using
It's going to be WAY more code to exactly cover all the strings that Python considers integers. I say just be pythonic on this one.
try/excepts all over the place, please just write a helper function:def represents_int(s):
try:
int(s)
except ValueError:
return False
else:
return True>>> print(represents_int("+123"))
True
>>> print(represents_int("10.0"))
FalseIt's going to be WAY more code to exactly cover all the strings that Python considers integers. I say just be pythonic on this one.
Code Snippets
def represents_int(s):
try:
int(s)
except ValueError:
return False
else:
return True>>> print(represents_int("+123"))
True
>>> print(represents_int("10.0"))
FalseContext
Stack Overflow Q#1265665, score: 517
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