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How can I use optional chaining with arrays and functions?

Submitted by: @import:stackoverflow-api··
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functionswithhowarraysanduseoptionalchainingcan

Problem

I'm trying to use optional chaining with an array instead of an object but not sure how to do that:

Here's what I'm trying to do myArray.filter(x => x.testKey === myTestKey)?[0].
Also trying similar thing with a function:

let x = {a: () => {}, b: null}
console.log(x?b());


But it's giving a similar error - how can I use optional chaining with an array or a function?

Solution

You need to put a . after the ? to use optional chaining:

myArray.filter(x => x.testKey === myTestKey)?.[0]


Playground link

Using just the ? alone makes the compiler think you're trying to use the conditional operator (and then it throws an error since it doesn't see a : later)

Optional chaining isn't just a TypeScript thing - it is a finished proposal in plain JavaScript too.

It can be used with bracket notation like above, but it can also be used with dot notation property access:



const obj = {
prop2: {
nested2: 'val2'
}
};

console.log(
obj.prop1?.nested1,
obj.prop2?.nested2
);




And with function calls:



const obj = {
fn2: () => console.log('fn2 running')
};

obj.fn1?.();
obj.fn2?.();

Code Snippets

myArray.filter(x => x.testKey === myTestKey)?.[0]

Context

Stack Overflow Q#59623674, score: 589

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