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How can I use optional chaining with arrays and functions?
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Problem
I'm trying to use optional chaining with an array instead of an object but not sure how to do that:
Here's what I'm trying to do
Also trying similar thing with a function:
But it's giving a similar error - how can I use optional chaining with an array or a function?
Here's what I'm trying to do
myArray.filter(x => x.testKey === myTestKey)?[0].Also trying similar thing with a function:
let x = {a: () => {}, b: null}
console.log(x?b());But it's giving a similar error - how can I use optional chaining with an array or a function?
Solution
You need to put a
Playground link
Using just the
Optional chaining isn't just a TypeScript thing - it is a finished proposal in plain JavaScript too.
It can be used with bracket notation like above, but it can also be used with dot notation property access:
And with function calls:
. after the ? to use optional chaining:myArray.filter(x => x.testKey === myTestKey)?.[0]Playground link
Using just the
? alone makes the compiler think you're trying to use the conditional operator (and then it throws an error since it doesn't see a : later)Optional chaining isn't just a TypeScript thing - it is a finished proposal in plain JavaScript too.
It can be used with bracket notation like above, but it can also be used with dot notation property access:
const obj = {
prop2: {
nested2: 'val2'
}
};
console.log(
obj.prop1?.nested1,
obj.prop2?.nested2
);
And with function calls:
const obj = {
fn2: () => console.log('fn2 running')
};
obj.fn1?.();
obj.fn2?.();Code Snippets
myArray.filter(x => x.testKey === myTestKey)?.[0]Context
Stack Overflow Q#59623674, score: 589
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