Simple way to repeat a string

I'm looking for a simple commons method or operator that allows me to repeat some string n times. I know I could write this using a for loop, but I wish to avoid for loops whenever necessary and a simple direct method should exist somewhere.

String str = "abc";
String repeated = str.repeat(3);

repeated.equals("abcabcabc");

Related to:

repeat string javascript
Create NSString by repeating another string a given number of times

Edited

I try to avoid for loops when they are not completely necessary because:

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They add to the number of lines of code even if they are tucked away in another function.

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Someone reading my code has to figure out what I am doing in that for loop. Even if it is commented and has meaningful variables names, they still have to make sure it is not doing anything "clever".

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Programmers love to put clever things in for loops, even if I write it to "only do what it is intended to do", that does not preclude someone coming along and adding some additional clever "fix".

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They are very often easy to get wrong. For loops involving indexes tend to generate off by one bugs.

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For loops often reuse the same variables, increasing the chance of really hard to find scoping bugs.

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For loops increase the number of places a bug hunter has to look.

String::repeat

". ".repeat(7)  // Seven period-with-space pairs: . . . . . . .

New in Java 11 is the method String::repeat that does exactly what you asked for:

String str = "abc";
String repeated = str.repeat(3);
repeated.equals("abcabcabc");

Its Javadoc says:

/**
 * Returns a string whose value is the concatenation of this
 * string repeated {@code count} times.
 * 
 * If this string is empty or count is zero then the empty
 * string is returned.
 *
 * @param count number of times to repeat
 *
 * @return A string composed of this string repeated
 * {@code count} times or the empty string if this
 * string is empty or count is zero
 *
 * @throws IllegalArgumentException if the {@code count} is
 * negative.
 *
 * @since 11
 */

Stack Overflow Q#1235179, score: 422