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Convert a string representation of a hex dump to a byte array using Java?
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Problem
I am looking for a way to convert a long string (from a dump), that represents hex values into a byte array.
I couldn't have phrased it better than the person that posted the same question here.
But to keep it original, I'll phrase it my own way: suppose I have a string
what should I do?
I am a Java novice and ended up using
I couldn't have phrased it better than the person that posted the same question here.
But to keep it original, I'll phrase it my own way: suppose I have a string
"00A0BF" that I would like interpreted as thebyte[] {0x00,0xA0,0xBf}what should I do?
I am a Java novice and ended up using
BigInteger and watching out for leading hex zeros. But I think it is ugly and I am sure I am missing something simple.Solution
Update (2021) - Java 17 now includes
For older versions of Java:
Here's a solution that I think is better than any posted so far:
Reasons why it is an improvement:
-
Safe with leading zeros (unlike BigInteger) and with negative byte values (unlike Byte.parseByte)
-
Doesn't convert the String into a
-
No library dependencies that may not be available
Feel free to add argument checking via
java.util.HexFormat (only took 25 years):HexFormat.of().parseHex(s)For older versions of Java:
Here's a solution that I think is better than any posted so far:
/* s must be an even-length string. */
public static byte[] hexStringToByteArray(String s) {
int len = s.length();
byte[] data = new byte[len / 2];
for (int i = 0; i < len; i += 2) {
data[i / 2] = (byte) ((Character.digit(s.charAt(i), 16) << 4)
+ Character.digit(s.charAt(i+1), 16));
}
return data;
}Reasons why it is an improvement:
-
Safe with leading zeros (unlike BigInteger) and with negative byte values (unlike Byte.parseByte)
-
Doesn't convert the String into a
char[], or create StringBuilder and String objects for every single byte.-
No library dependencies that may not be available
Feel free to add argument checking via
assert or exceptions if the argument is not known to be safe.Code Snippets
/* s must be an even-length string. */
public static byte[] hexStringToByteArray(String s) {
int len = s.length();
byte[] data = new byte[len / 2];
for (int i = 0; i < len; i += 2) {
data[i / 2] = (byte) ((Character.digit(s.charAt(i), 16) << 4)
+ Character.digit(s.charAt(i+1), 16));
}
return data;
}Context
Stack Overflow Q#140131, score: 796
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