patterncppCritical
What are the rules for calling the base class constructor?
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Problem
What are the C++ rules for calling the base class constructor from a derived class?
For example, I know in Java, you must do it as the first line of the subclass constructor (and if you don't, an implicit call to a no-arg super constructor is assumed - giving you a compile error if that's missing).
For example, I know in Java, you must do it as the first line of the subclass constructor (and if you don't, an implicit call to a no-arg super constructor is assumed - giving you a compile error if that's missing).
Solution
Base class constructors are automatically called for you if they have no argument. If you want to call a superclass constructor with an argument, you must use the subclass's constructor initialization list. Unlike Java, C++ supports multiple inheritance (for better or worse), so the base class must be referred to by name, rather than "super()".
More info on the constructor's initialization list here and here.
class SuperClass
{
public:
SuperClass(int foo)
{
// do something with foo
}
};
class SubClass : public SuperClass
{
public:
SubClass(int foo, int bar)
: SuperClass(foo) // Call the superclass constructor in the subclass' initialization list.
{
// do something with bar
}
};More info on the constructor's initialization list here and here.
Code Snippets
class SuperClass
{
public:
SuperClass(int foo)
{
// do something with foo
}
};
class SubClass : public SuperClass
{
public:
SubClass(int foo, int bar)
: SuperClass(foo) // Call the superclass constructor in the subclass' initialization list.
{
// do something with bar
}
};Context
Stack Overflow Q#120876, score: 1190
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