patterngoCritical
Make a URL-encoded POST request using `http.NewRequest(...)`
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urlrequestusinghttppostmakeencodednewrequest
Problem
I want to make a POST request to an API sending my data as a
As I response, I get always a
application/x-www-form-urlencoded content type. Due to the fact that I need to manage the request headers, I'm using the http.NewRequest(method, urlStr string, body io.Reader) method to create a request. For this POST request I append my data query to the URL and leave the body empty, something like this:package main
import (
"bytes"
"fmt"
"net/http"
"net/url"
"strconv"
)
func main() {
apiUrl := "https://api.com"
resource := "/user/"
data := url.Values{}
data.Set("name", "foo")
data.Add("surname", "bar")
u, _ := url.ParseRequestURI(apiUrl)
u.Path = resource
u.RawQuery = data.Encode()
urlStr := fmt.Sprintf("%v", u) // "https://api.com/user/?name=foo&surname=bar"
client := &http.Client{}
r, _ := http.NewRequest("POST", urlStr, nil)
r.Header.Add("Authorization", "auth_token=\"XXXXXXX\"")
r.Header.Add("Content-Type", "application/x-www-form-urlencoded")
r.Header.Add("Content-Length", strconv.Itoa(len(data.Encode())))
resp, _ := client.Do(r)
fmt.Println(resp.Status)
}As I response, I get always a
400 BAD REQUEST. I believe the problem relies on my request and the API does not understand which payload I am posting. I'm aware of methods like Request.ParseForm, not really sure how to use it in this context though. Maybe am I missing some further Header, maybe is there a better way to send payload as a application/json type using the body parameter?Solution
URL-encoded payload must be provided on the
Based on the sample code:
body parameter of the http.NewRequest(method, urlStr string, body io.Reader) method, as a type that implements io.Reader interface.Based on the sample code:
package main
import (
"fmt"
"net/http"
"net/url"
"strconv"
"strings"
)
func main() {
apiUrl := "https://api.com"
resource := "/user/"
data := url.Values{}
data.Set("name", "foo")
data.Set("surname", "bar")
u, _ := url.ParseRequestURI(apiUrl)
u.Path = resource
urlStr := u.String() // "https://api.com/user/"
client := &http.Client{}
r, _ := http.NewRequest(http.MethodPost, urlStr, strings.NewReader(data.Encode())) // URL-encoded payload
r.Header.Add("Authorization", "auth_token=\"XXXXXXX\"")
r.Header.Add("Content-Type", "application/x-www-form-urlencoded")
resp, _ := client.Do(r)
fmt.Println(resp.Status)
}resp.Status is 200 OK this way.Code Snippets
package main
import (
"fmt"
"net/http"
"net/url"
"strconv"
"strings"
)
func main() {
apiUrl := "https://api.com"
resource := "/user/"
data := url.Values{}
data.Set("name", "foo")
data.Set("surname", "bar")
u, _ := url.ParseRequestURI(apiUrl)
u.Path = resource
urlStr := u.String() // "https://api.com/user/"
client := &http.Client{}
r, _ := http.NewRequest(http.MethodPost, urlStr, strings.NewReader(data.Encode())) // URL-encoded payload
r.Header.Add("Authorization", "auth_token=\"XXXXXXX\"")
r.Header.Add("Content-Type", "application/x-www-form-urlencoded")
resp, _ := client.Do(r)
fmt.Println(resp.Status)
}Context
Stack Overflow Q#19253469, score: 274
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