Is it possible for one struct to extend an existing struct, keeping all the fields?

Using rust 1.2.0

Problem

I'm still in the process of learning Rust (coming from a Javascript background) and am trying to figure out if it is possible for one struct StructB to extend an existing struct StructA such that StructB has all the fields defined on StructA.

In Javascript (ES6 syntax) I could essentially do something like this...

class Person {
    constructor (gender, age) {
        this.gender = gender;
        this.age = age;
    }
}
class Child extends Person {
    constructor (name, gender, age) {
        super(gender, age);
        this.name = name;
    }
}

Constraints

• StructA is from an external cargo package that I have no control over.

Current Progress

I found this blog post on single-inheritance which sounds like exactly what I need.

But trying to implement it resulted in this error message error: virtual structs have been removed from the language. Some searching later and I found out that it had been implemented and then removed per RFC-341 rather quickly.

Also found this thread about using traits, but since StructA is from an external cargo package I don't think it is possible for me to turn it into a trait.

So what would be the correct way to accomplish this in Rust?

There is nothing that exactly matches that. There are two concepts that come to mind.

-
Structural composition

struct Person {
    age: u8,
}

struct Child {
    person: Person,
    has_toy: bool,
}

impl Person {
    fn new(age: u8) -> Self {
        Person { age: age }
    }

    fn age(&self) -> u8 {
        self.age
    }
}

impl Child {
    fn new(age: u8, has_toy: bool) -> Self {
        Child { person: Person::new(age), has_toy: has_toy }
    }

    fn age(&self) -> u8 {
        self.person.age()
    }
}

fn main() {
    let p = Person::new(42);
    let c = Child::new(7, true);

    println!("I am {}", p.age());
    println!("My child is {}", c.age());
}

You can simply embed one struct into another. The memory layout is nice and compact, but you have to manually delegate all the methods from Person to Child or lend out a &Person.

-
Traits

trait SayHi {
    fn say_hi(&self);
}

struct Person {
    age: u8,
}

struct Child {
    age: u8,
    has_toy: bool,
}

impl SayHi for Person {
    fn say_hi(&self) {
        println!("Greetings. I am {}", self.age)
    }
}

impl SayHi for Child {
    fn say_hi(&self) {
        if self.has_toy {
            println!("I'm only {}, but I have a toy!", self.age)
        } else {
            println!("I'm only {}, and I don't even have a toy!", self.age)
        }
    }
}

fn greet(thing: T)
    where T: SayHi
{
    thing.say_hi()
}

fn main() {
    let p = Person { age: 42 };
    let c = Child { age: 7, has_toy: true };

    greet(p);
    greet(c);
}

You can combine these two concepts, of course.

As DK. mentions, you could choose to implement Deref or DerefMut. However, I do not agree that these traits should be used in this manner. My argument is akin to the argument that using classical object-oriented inheritance simply for code reuse is the wrong thing. "Favor composition over inheritance" => "favor composition over Deref". However, I do hold out hope for a language feature that enables succinct delegation, reducing the annoyance of composition.

Stack Overflow Q#32552593, score: 119