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How does one round a floating point number to a specified number of digits?
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howspecifiedfloatingdigitspointrounddoesnumberone
Problem
How does one round a f64 floating point number in Rust to a specified number of digits?
Solution
If you want this just for display purposes, use the formatting syntax built into
If you want to put the rounded number in a string, use the
If you want to round a number and get the result back as another number, then multiply the number by the given power of 10, call
playground
This prints
If the number of decimal places isn't known at compile time, one could use
Note that this will breakdown for very large numbers; specifically, numbers larger than
println!(). For example, to print a number rounded to 2 decimal places use the {:.2} format specifier:fn main() {
let x = 12.34567;
println!("{:.2}", x);
}If you want to put the rounded number in a string, use the
format!() macro.If you want to round a number and get the result back as another number, then multiply the number by the given power of 10, call
round, and divide by the same power, e.g. to round to 2 decimal places, use 102 = 100.fn main() {
let x = 12.34567_f64;
let y = (x * 100.0).round() / 100.0;
println!("{:.5} {:.5}", x, y);
}playground
This prints
12.34567 12.35000. If the number of decimal places isn't known at compile time, one could use
powi to efficiently compute the relevant power. Note that this will breakdown for very large numbers; specifically, numbers larger than
std::f64::MAX / power (where power is the power of ten, e.g. 100 in the example above) will become infinity in the multiplication, and remain infinity after. However, f64 cannot represent any fractional places for numbers larger than 253 (i.e. they're always integers), so one can special case such large numbers to just return themselves.Code Snippets
fn main() {
let x = 12.34567;
println!("{:.2}", x);
}fn main() {
let x = 12.34567_f64;
let y = (x * 100.0).round() / 100.0;
println!("{:.5} {:.5}", x, y);
}Context
Stack Overflow Q#28655362, score: 192
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