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How do I borrow a reference to what is inside an Option<T>?
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howinsideoptionborrowwhatreference
Problem
How do I pull a reference out of an
Specifically, I want to borrow a reference to a
...but that results in:
Hm, ok. Maybe not. It looks vaguely like what I want to do is related to
...but, that doesn't work either.
Full code I'm having trouble with:
```
#[derive(Debug)]
struct Foo;
#[derive(Debug)]
struct Bar {
data: Option>,
}
#[derive(Debug)]
enum BarErr {
Nope,
}
impl Bar {
fn borrow(&mut self) -> Result, Ba
Option and pass it back with the specific lifespan of the caller? Specifically, I want to borrow a reference to a
Box from a Bar that has an Option> in it. I thought I would be able to do:impl Bar {
fn borrow(&mut self) -> Result, BarErr> {
match self.data {
Some(e) => Ok(&e),
None => Err(BarErr::Nope),
}
}
}...but that results in:
error: e does not live long enough
--> src/main.rs:17:28
|
17 | Some(e) => Ok(&e),
| ^ does not live long enough
18 | None => Err(BarErr::Nope),
19 | }
| - borrowed value only lives until here
|
note: borrowed value must be valid for the anonymous lifetime #1 defined on the body at 15:54...
--> src/main.rs:15:55
|
15 | fn borrow(&mut self) -> Result, BarErr> {
| _______________________________________________________^ starting here...
16 | | match self.data {
17 | | Some(e) => Ok(&e),
18 | | None => Err(BarErr::Nope),
19 | | }
20 | | }
| |_____^ ...ending here
error[E0507]: cannot move out of borrowed content
--> src/main.rs:16:15
|
16 | match self.data {
| ^^^^ cannot move out of borrowed content
17 | Some(e) => Ok(&e),
| - hint: to prevent move, use ref e or ref mut e
Hm, ok. Maybe not. It looks vaguely like what I want to do is related to
Option::as_ref, like maybe I could do:impl Bar {
fn borrow(&mut self) -> Result, BarErr> {
match self.data {
Some(e) => Ok(self.data.as_ref()),
None => Err(BarErr::Nope),
}
}
}...but, that doesn't work either.
Full code I'm having trouble with:
```
#[derive(Debug)]
struct Foo;
#[derive(Debug)]
struct Bar {
data: Option>,
}
#[derive(Debug)]
enum BarErr {
Nope,
}
impl Bar {
fn borrow(&mut self) -> Result, Ba
Solution
First of all, you don't need
When matching, you should match
&mut self.When matching, you should match
e as a reference. You are trying to return a reference of e, but the lifetime of it is only for that match statement.enum BarErr {
Nope
}
struct Foo;
struct Bar {
data: Option>
}
impl Bar {
fn borrow(&self) -> Result {
match self.data {
Some(ref x) => Ok(x),
None => Err(BarErr::Nope)
}
}
}Code Snippets
enum BarErr {
Nope
}
struct Foo;
struct Bar {
data: Option<Box<Foo>>
}
impl Bar {
fn borrow(&self) -> Result<&Foo, BarErr> {
match self.data {
Some(ref x) => Ok(x),
None => Err(BarErr::Nope)
}
}
}Context
Stack Overflow Q#22282117, score: 31
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