patternrustMajor

Is it possible to unpack a tuple into function arguments?

Submitted by: @import:stackoverflow-api·Mar 10, 2026·

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unpackpossiblefunctiontupleintoarguments

Problem

If I want to unpack a tuple and pass it as arguments is there a way to do this:

//Does not compile
fn main() {
    let tuple = (10, Vec::new());
    foo(tuple);
}
fn foo(a: i32, b: Vec) {
    //Does stuff.
}

Instead of having to do this:

fn main() {
    let tuple = (10, Vec::new());
    foo(tuple.0, tuple.1);
}
fn foo(a: i32, b: Vec) {
    //Does stuff.
}

On a nightly compiler:

#![feature(fn_traits)]

fn main() {
    let tuple = (10, Vec::new());
    std::ops::Fn::call(&foo, tuple);
}
fn foo(a: i32, b: Vec) {
}

There is AFAIK no stable way to do that.

#![feature(fn_traits)]

fn main() {
    let tuple = (10, Vec::new());
    std::ops::Fn::call(&foo, tuple);
}
fn foo(a: i32, b: Vec<i32>) {
}

Stack Overflow Q#39878382, score: 51

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