patternrustMajor
What does the ampersand (&) before `self` mean in Rust?
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selftheampersanddoesmeanbeforerustwhat
Problem
I've seen this code in the Rust documentation:
what does the
fn eat(&self) {
println!("{} is done eating.", self.name);
}what does the
& in &self mean?Solution
This means you'll be passing in a reference to the object, as opposed to moving the object itself. It's important to distinguish this because if your function looked like:
and you tried calling it then using the variable after, you'd get an error
because when you don't specify
Now switch
fn eat(self) {
println!("{} is done eating.", self.name);
}and you tried calling it then using the variable after, you'd get an error
object = Foo::new();
object.eat();
object.something(); // error, because you moved object in eatbecause when you don't specify
&, rust moves the value into the function and your original binding no longer has ownership. check out this minimal example I created (playground version):struct Foo {
x : u32
}
impl Foo {
fn eat(self) {
println!("eating");
}
fn something(&self) {
println!("else");
}
}
fn main() {
println!("Hello, world!");
let g = Foo { x: 5 };
g.eat();
g.something(); // if this comes before eat, no errors because we arent moving
}Now switch
something to be called before eat. Because something only takes a reference, g still has ownership and you can continue on. eat on the other hand moves g and you no longer can use g.Code Snippets
fn eat(self) {
println!("{} is done eating.", self.name);
}object = Foo::new();
object.eat();
object.something(); // error, because you moved object in eatstruct Foo {
x : u32
}
impl Foo {
fn eat(self) {
println!("eating");
}
fn something(&self) {
println!("else");
}
}
fn main() {
println!("Hello, world!");
let g = Foo { x: 5 };
g.eat();
g.something(); // if this comes before eat, no errors because we arent moving
}Context
Stack Overflow Q#31908636, score: 78
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