How can I convert a buffer of a slice of bytes (&[u8]) to an integer?

I am reading raw data from a file and I want to convert it to an integer:

fn main() {
    let buf: &[u8] = &[0, 0, 0, 1];
    let num = slice_to_i8(buf);
    println!("1 == {}", num);
}

pub fn slice_to_i8(buf: &[u8]) -> i32 {
    unimplemented!("what should I do here?")
}

I would do a cast in C, but what do I do in Rust?

I'd suggest using the byteorder crate (which also works in a no-std environment):

use byteorder::{BigEndian, ReadBytesExt}; // 1.2.7

fn main() {
    let mut buf: &[u8] = &[0, 0, 0, 1];
    let num = buf.read_u32::().unwrap();

    assert_eq!(1, num);
}

This handles oddly-sized slices and automatically advances the buffer so you can read multiple values.

As of Rust 1.32, you can also use the from_le_bytes / from_be_bytes / from_ne_bytes inherent methods on integers:

fn main() {
    let buf = [0, 0, 0, 1];
    let num = u32::from_be_bytes(buf);

    assert_eq!(1, num);
}

These methods only handle fixed-length arrays to avoid dealing with the error when not enough data is present. If you have a slice, you will need to convert it into an array.

See also:

• How to get a slice as an array in Rust?

• How to convert a slice into an array reference?

Stack Overflow Q#29307474, score: 66