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Does the time complexity of a problem change with encoding of the problem?
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Problem
Suppose I have a decision problem $D$ and I encode it to a language $L \subset \{0,1\}^*$. Now, I can also encode it to a different language $L'$.
Is there any theorem relating the time complexity of $L$ and $L'$?
How does the time complexity of a problem change with different encodings of the same problem?
Is there any theorem relating the time complexity of $L$ and $L'$?
How does the time complexity of a problem change with different encodings of the same problem?
Solution
Yes, the complexity depends on the encoding. The only thing you can be sure of is that if translating from encoding $L$ to encoding $L'$ or vice versa has the complexity $f$, and $D$ can be solved with complexity $g$, then $D'$ (same problem expressed with the encoding $L'$) can be solved with complexity $O(f+g)$ by going back and forth between encodings.
It isn't just a matter of length of the encoding. To give a simple example, let $L$ be positive integers represented in binary, and $L'$ be positive integers represented by their prime factorization. There is a polynomial bound in the size of one representation in terms of the other. Yet for a long time, it was not known whether primality testing can be solved in polynomial time in the binary representation; but in the factorization representation, it's trivially polynomial (probably $O(1)$ depending on the representation details).
Or consider the decision problem “is integer $n$ a member of set $S$”. If the set is represented by an unordered list of integers, this problem evidently requires at least linear time. But if the set is represented by a balanced search tree, lookup time is polylogarithmic in the size of the set.
In most concrete cases, there is an evident representation that everyone assumes, or more precisely there is a class of representations that are all equivalent up to a transformation that takes negligible time. But sometimes the representation is relevant, most frequently when analyzing data structures with more precision than polynomial time.
It isn't just a matter of length of the encoding. To give a simple example, let $L$ be positive integers represented in binary, and $L'$ be positive integers represented by their prime factorization. There is a polynomial bound in the size of one representation in terms of the other. Yet for a long time, it was not known whether primality testing can be solved in polynomial time in the binary representation; but in the factorization representation, it's trivially polynomial (probably $O(1)$ depending on the representation details).
Or consider the decision problem “is integer $n$ a member of set $S$”. If the set is represented by an unordered list of integers, this problem evidently requires at least linear time. But if the set is represented by a balanced search tree, lookup time is polylogarithmic in the size of the set.
In most concrete cases, there is an evident representation that everyone assumes, or more precisely there is a class of representations that are all equivalent up to a transformation that takes negligible time. But sometimes the representation is relevant, most frequently when analyzing data structures with more precision than polynomial time.
Context
StackExchange Computer Science Q#13640, answer score: 8
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