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Describing explicitly the MyHill-Nerode classes created by a language
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Problem
I want to practice proving a language is regular or not using the MyHill-Nerode theorm, but for that I need to be able to describe the classes. Here's my practice attempt:
For the language
$$L=\{\omega \in \{a,b\}^* \colon \omega \text{ contains at most 1 } 'a' \}$$
The classes are
$$M_1=\{\omega \in b^*\}$$
$$M_2=\{\omega \in b^ab^\}$$
$$M_3=\{\omega \in b^ab^a(a\cup b)^*\}$$
Now, the way I understand it I need to prove 2 things:
$$ux\in L \iff vx\in L$$
$$ux\in L,vx\notin L$$
Am I right about how I described the classes, and about how to prove it?
For the language
$$L=\{\omega \in \{a,b\}^* \colon \omega \text{ contains at most 1 } 'a' \}$$
The classes are
$$M_1=\{\omega \in b^*\}$$
$$M_2=\{\omega \in b^ab^\}$$
$$M_3=\{\omega \in b^ab^a(a\cup b)^*\}$$
Now, the way I understand it I need to prove 2 things:
- For each $u,v\in M_i (1\le i\le 3)$ and for each $x\in \Sigma^*$
$$ux\in L \iff vx\in L$$
- There exists $u\in M_i,v\in M_j(1\le i \neq j \le 3)$ and $x\in \Sigma^*$ such that
$$ux\in L,vx\notin L$$
Am I right about how I described the classes, and about how to prove it?
Solution
Your classes are correct, and one can also describe them in words: words containing no $a$, words containing a single $a$, words containing at least two $a$s. When described in this fashion, it is clear that the every word belongs to exactly one class.
However, there is no reason to use the Myhill–Nerode criterion to prove that a language is regular. Instead, you can use its vast generalization and give a DFA or NFA for the language. In the other direction, there is no need to describe all classes, only infinitely many; this already shows the language is not regular.
However, there is no reason to use the Myhill–Nerode criterion to prove that a language is regular. Instead, you can use its vast generalization and give a DFA or NFA for the language. In the other direction, there is no need to describe all classes, only infinitely many; this already shows the language is not regular.
Context
StackExchange Computer Science Q#28075, answer score: 4
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