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Complement of CFL is Recursive

Submitted by: @import:stackexchange-cs··
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complementcflrecursive

Problem

If CFL are not closed under complementation, it means that if a language '$L$' is CFL then its compliment $L^C$ is not CFL. Then how can we discuss about $L^C$ being recursive?

My doubt arose because I think if a language cannot be decided CFL or not then how can it be declared Recursive ?

Solution

You can think of it as " every CFL is Recursive".

And Recursive languages are closed under complementation.

Therefore, if a language $L$ is CFL then it is also recursive and hence, $L^C$ is also recursive.

Context

StackExchange Computer Science Q#65798, answer score: 15

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