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What is the difference between strong normalization and weak normalization in the context of rewrite systems?

Submitted by: @import:stackexchange-cs··
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Problem

In the context of rewriting systems, how does strong normalization differ from weak normalization?

Solution

Weak normalization means that any term has a terminating rewriting sequence, i.e. admits a finite amount of rewritings which lead to a normal form (no more rewritings from that).

Strong normalization means that any term can never be rewritten infinitely many times. Any maximal rewriting sequence eventually reaches a normal form (hence it is finite).

For instance:

$$
S \rightarrow (SS) \qquad
S \rightarrow A
$$

is weakly normalizing (given any term, we can rewrite every $S$ into an $A$, after which normal form is reached) but not strongly normalizing ($S \rightarrow (SS) \rightarrow ((S S) S) \rightarrow \cdots$).

It is immediate to prove that strong normalization implies weak normalization.

Context

StackExchange Computer Science Q#68080, answer score: 14

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