Binary search in a sorted JavaScript array

The binary search algorithm is a fast and efficient way to find the index of a given element in a sorted array. It works by repeatedly dividing the search interval in half, narrowing down the possible locations of the element.
A binary search is much faster than a linear search, especially for large arrays, as it has a time complexity of O(log n). However, it requires the array to be sorted beforehand.
In order to implement the algorithm, we need to keep track of the left and right boundaries of the search interval, and repeatedly divide it in half until the element is found or the interval is empty. The boundaries are initialized to 0 and the length of the array, respectively.
Then, using a while loop, we calculate the middle index of the current interval and compare the element at that index with the target element. If the element is found, we return the index. Otherwise, we update the boundaries based on the comparison and continue the search.
If the element is not found after the loop, we return -1 to indicate that the element is not present in the array.

const binarySearch = (arr, item) => {
  let l = 0, r = arr.length - 1;

  while (l <= r) {
    const mid = Math.floor((l + r) / 2);
    const guess = arr[mid];

    if (guess === item) return mid;
    if (guess > item) r = mid - 1;
    else l = mid + 1;
  }

  return -1;
};

binarySearch([1, 2, 3, 4, 5], 1); // 0
binarySearch([1, 2, 3, 4, 5], 5); // 4
binarySearch([1, 2, 3, 4, 5], 6); // -1

In order to implement the algorithm, we need to keep track of the left and right boundaries of the search interval, and repeatedly divide it in half until the element is found or the interval is empty. The boundaries are initialized to 0 and the length of the array, respectively.
Then, using a while loop, we calculate the middle index of the current interval and compare the element at that index with the target element. If the element is found, we return the index. Otherwise, we update the boundaries based on the comparison and continue the search.
If the element is not found after the loop, we return -1 to indicate that the element is not present in the array.
> [!NOTE]
>
> This implementation does not account for duplicate values in the array.

From 30-seconds-of-code: binary-search