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patternsqlMinor

Will these queries return the same results?

Submitted by: @import:stackexchange-dba··
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samethethesereturnwillresultsqueries

Problem

I have this simple query:

SELECT 
    friend_id
FROM
    default_friend
WHERE
    user_id = 1


And the results are below:

+-----------+
| friend_id |
+-----------+
|      2250 |
|      4901 |
|      7187 |
|      9337 |
|      9843 |
+-----------+


Now I have this query too a bit more complex:

SELECT 
    friend_id, user_id, approved
FROM
    default_friend
WHERE
    user_id = 1
        AND (friend_id IN (SELECT 
            friend_id
        FROM
            default_friend
        WHERE
            user_id = 1))
        AND approved = 0


My question is: will the SELECT into the second query return the same data as the data returned by first query? Meaning friend_id = 2250, 4901, 7187, 9337, 9843 or I need to run the first and the programmatically split the results and build the second one? Also I'll like to know which way is more optimum!

Solution

No, you don't have to run the first query, get the results, build the second one dynamically and then run it.

And you don't need this complex second query either. The simple one will suffice:

SELECT 
    friend_id, user_id, approved
FROM
    default_friend
WHERE
    user_id = 1
  AND
    approved = 0 ;


And you don't really need the user_id and the approved in the SELECT list either. They are going to be 1 and 0 in all rows, aren't they?

So, the question is. Why don't you just keep the original, 1st query, adding only the additional condition (approved = 0) ?:

SELECT 
    friend_id
FROM
    default_friend
WHERE
    user_id = 1
  AND
    approved = 0 ;

Code Snippets

SELECT 
    friend_id, user_id, approved
FROM
    default_friend
WHERE
    user_id = 1
  AND
    approved = 0 ;
SELECT 
    friend_id
FROM
    default_friend
WHERE
    user_id = 1
  AND
    approved = 0 ;

Context

StackExchange Database Administrators Q#22682, answer score: 6

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