MySQL: Unique constraint on large column

I am trying to create an InnoDB table that contains a VARCHAR column that can hold up to 3071 characters. I would like to enforce a UNIQUE constraint on the data of this column.

MySQL appears to enforce constraints using an index. In InnoDB, index sizes appear to be limited to 767 bytes - not nearly enough for the VARCHAR(3071) column that is holding the data.

Any thoughts on how to have the database enforce uniqueness of the data, without compromising on maximum data length or the usage of InnoDB?

You do not want a gigantic gen_clust_index (Internal Clustered Index). That size is ungodly huge even for a secondary index.

You may have to resort to triggers or stored procedures to check for the key well in advance.

You could also think about performing an SHA1 function call using the VARCHAR(3071) field. SHA1 will return a 40-character field. This hash may be just what you need to index.

Suppose you have this

CREATE TABLE mytable
(
    id int not null auto_increment,
    txt VARCHAR(3071),
    primary key (id)
) ENGINE=InnODB;

and you want to make a UNIQUE index on txt. Try the SHA1 approach

CREATE TABLE mytablenew LIKE mytable;
ALTER TABLE mytable ADD txtsha1 CHAR(40);
ALTER TABLE mytable ADD UNIQUE KEY (txtsha1);
INSERT INTO mytablenew (id,txt,txtsha1)
SELECT id,txt,SHA1(txt) FROM mytable;

Then, count them

SELECT COUNT(1) FROM mytable;
SELECT COUNT(1) FROM mytablenew;

If the Counts are the Same, CONGRATULATIONS !!! Now you have a unique index of length 40. You can finish up with:

ALTER TABLE mytable RENAME mytableold;
ALTER TABLE mytablenew RENAME mytable;
DROP TABLE mytableold;

This could be more atomically as pointed out in the comments below:

RENAME TABLE mytable TO mytableold, mytablenew TO mytable;
DROP TABLE mytableold;

Perform this on whatever table you intend to have this big column. You have to remember to add the SHA1 of the data along with the data upon INSERT.

The odds of duplicate keys is 1 in 2 to the 160th power (that 1.4615016373309029182036848327163e+48. If I get the exact figure, I'll post it someday).

Give it a Try !!!

StackExchange Database Administrators Q#27190, answer score: 11