Mysql match on two columns and get count

How do I get a count of?

+---------+-------------+
|   col1  |   col2      |  
+---------+-------------+
|     Joe | April       |
|    Fred | May         |
|     Sam | April       | 
|     Joe | April       |
|    Mark | Jan         | 
|     Joe | Dec         |             
+---------+-------------+

In MYSQL how do I get a count on Names that match only if Month also match?
IE
Joe April should be only one...

@Abdul's answer just needs HAVING COUNT(*) > 1

The query shold look like this now

SELECT COUNT(*), col1 , col2 FROM test GROUP BY col1,col2 HAVING COUNT(*) > 1;

Here is the execution of it:

mysql> create table test(col1 varchar(20),col2 varchar(20));
Query OK, 0 rows affected (0.33 sec)

mysql> INSERT INTO test VALUES('Joe','April'),('Fred','May'),
    -> ('Sam','April'),('Joe','April'),('Mark','Jan'),('Joe','Dec');
Query OK, 6 rows affected (0.06 sec)
Records: 6  Duplicates: 0  Warnings: 0

mysql> SELECT COUNT(*), col1 , col2 FROM test GROUP BY col1,col2 HAVING COUNT(*) > 1;
+----------+------+-------+
| COUNT(*) | col1 | col2  |
+----------+------+-------+
|        2 | Joe  | April |
+----------+------+-------+
1 row in set (0.24 sec)

mysql>

If you do not care for the count, remove it from the SELECT clause

mysql> SELECT col1 , col2 FROM test GROUP BY col1,col2 HAVING COUNT(*) > 1;
+------+-------+
| col1 | col2  |
+------+-------+
| Joe  | April |
+------+-------+
1 row in set (0.00 sec)

mysql>

Give it a Try !!!

StackExchange Database Administrators Q#55603, answer score: 4