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Compare the structure of two MySQL Databases
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thedatabasesmysqltwostructurecompare
Problem
I have two MySQL databases that are very similar to each other. How can I find out the differences in tables, and the differences in columns in each table?
- the databases are in different schema.
- It's only the structure I want to compare, not the data.
Solution
Using INFORMATION_SCHEMA.COLUMNS, here is my proposed query
The output will be each the columns differences. You will see differences by data type, column type, and/or column position. You should quickly see if a table only appears in one one database and not another.
SELECT B.* FROM
(
SELECT DISTINCT table_name FROM
(
SELECT table_name,column_name,ordinal_position,data_type,column_type,COUNT(1) match_count
FROM information_schema.columns WHERE table_schema IN ('db1','db2')
GROUP BY table_name,column_name,ordinal_position,data_type,column_type
HAVING COUNT(1) = 1
) AA
) A INNER JOIN
(
SELECT table_schema,table_name,column_name,ordinal_position,data_type,column_type
FROM information_schema.columns WHERE table_schema IN ('db1','db2')
) B;
USING (table_name)
ORDER BY B.table_name,B,table_schema;The output will be each the columns differences. You will see differences by data type, column type, and/or column position. You should quickly see if a table only appears in one one database and not another.
Code Snippets
SELECT B.* FROM
(
SELECT DISTINCT table_name FROM
(
SELECT table_name,column_name,ordinal_position,data_type,column_type,COUNT(1) match_count
FROM information_schema.columns WHERE table_schema IN ('db1','db2')
GROUP BY table_name,column_name,ordinal_position,data_type,column_type
HAVING COUNT(1) = 1
) AA
) A INNER JOIN
(
SELECT table_schema,table_name,column_name,ordinal_position,data_type,column_type
FROM information_schema.columns WHERE table_schema IN ('db1','db2')
) B;
USING (table_name)
ORDER BY B.table_name,B,table_schema;Context
StackExchange Database Administrators Q#90015, answer score: 2
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