How to check if integer array overlaps with int4range?

PostgreSQL version: 9.5

I am trying to write a query that will check if an array of specified decades overlaps in a range. For example, I'd like to find all of the people employed at a company in the 1980's OR the 2000's. Let's say I have two date columns: start_date and end_date. Here's my best attempt so far:

SELECT * 
 FROM date_table 
WHERE int4range(EXTRACT(DECADE from start_date)::int, 
                EXTRACT(DECADE from end_date)::int) && (int4range(198, 200))

This query will check for anyone employed in the 1980s, 1990s, or the 2000s. I don't want to compare a range to another range; instead, it should be checking if any of the values in the array is contained in the range. How can I accomplish this? Is there another way I could be approaching this problem?

UPDATE

Thanks to the answer by joanolo, my working query is:

SELECT * 
 FROM date_table 
WHERE int4range(EXTRACT(DECADE from start_date)::int, 
                EXTRACT(DECADE from end_date)::int, '[]') @> ANY(ARRAY[198, 200])

You can use the ANY and ALL array element quantifiers, together with the @> contains element range operator.

If you want to know if ANY element of the array lies within your range, which is what, according to your comments, is what I interpret you want, you can use:

SELECT
    int4range(5, 8, '[]') @> ANY(ARRAY[1, 3, 5, 7]) AS some_are_in

(in this case, this will return TRUE, because both 5 and 7 are part of the range)

This nearly translates your request (but reversing it): Does the range contain ANY of the elements of the array?

If you would like to know that they're all in, you'd use ALL instead of ANY:

SELECT
    int4range(5, 8, '[]') @> ALL(ARRAY[1, 3, 5, 7]) AS all_are_in

(in this case, this will return false, because 1 and 3 are not part of the range)

You can find these and some other examples at dbfiddle here

StackExchange Database Administrators Q#179376, answer score: 3