Print an integer and its digits reversed

This Common Lisp program is an exercise to print an integer and its digits reversed to the screen:

(defun read-number () (format t "Enter a number: ~%") (read))

(defun reverse-string (the-string) 
  (if (eq (length the-string) 0) 
    "" 
    (concatenate 'string (reverse-string (subseq the-string 1)) (subseq the-string 0 1))))

(defun reverse-digits (the-number) (reverse-string (write-to-string the-number)))

(let ((the-number (read-number)))
  (format t "N->: ~a~%<-N: ~a~%" the-number (reverse-digits the-number)))

This problem is more about numbers than strings, so I felt the need to post a non-string-based solution. I've got my original Scheme version, and a Common Lisp adaptation of same.

Scheme version:

(define (reverse-digits n)
  (let loop ((n n) (r 0))
    (if (zero? n) r
        (loop (quotient n 10) (+ (* r 10) (remainder n 10))))))

Common Lisp translation of the Scheme version:

(defun reverse-digits (n)
  (labels ((next (n v)
             (if (zerop n) v
                 (multiple-value-bind (q r)
                     (truncate n 10)
                   (next q (+ (* v 10) r))))))
    (next n 0)))

StackExchange Code Review Q#1219, answer score: 4