Scripting language parser

I'm making a scripting language parser and it's shaping up well but it takes about 30ms to do 30 or so odd/even checks.

Profiler tells me that it's taking most of the time in the InvokeOperator.Operate function but that doesn't tell me a lot because the Operate call the Run method on the CodeBlock which in turn again calls the Operate call and makes it very hard to actually determine what's taking as long.

Here's the Github repo

Here are the most important bits of the code:

Stack solvingStack = new Stack();
for ( int i = 0 ; i < value.Count ; ++i )
{
   if ( value[ i ] is Operator )
   {
      Operator op = (Operator)value[ i ];
      if ( op.Type == OperatorType.PrefixUnary || op.Type == OperatorType.SufixUnary )
      {
         op.Operate( ( solvingStack.Pop() as Value ), new NoValue() );
      } else
      {
         Value second = (Value)solvingStack.Pop();
         Value result = op.Operate( ( solvingStack.Pop() as Value ), second );
         solvingStack.Push( result );
      }
   } else
   {
      solvingStack.Push( value[ i ] );
   }
}
Compiler.ExitScope();
if ( solvingStack.Count == 0 ) return new NoValue();
else return (Value)solvingStack.Peek();

It's how the code is parsed after the infix expression is turned into RPN.
A token can be an operator or a value and a value can be a literal, identifier, codeblock.

A somewhat special case is a function because it's not parsed to RPN directly but only the code inside of it is. Then is there's an invoke operator, it takes the array of arguments that was provided and the function before it and runs the function (which inherits from CodeBlock, so it also runs the same thing that is shown here).

What each operator does on different types of values is determined by the operator itself in the Operators.cs file.

I am not sure if these are bottlenecks, but they are at least performance improvements.

-
Replace Stack with Stack since you are only pushing/popping Value. This way there is no need to do expensive casts.

-
You can replace

if ( value[ i ] is Operator )
{
    Operator op = (Operator)value[ i ];

with

Operator op = value[ i ] as Operator;
if ( op != null ) // it was an Operator

to have only one typecheck (x as y) instead of two (x is y and (y) x).

-
You can replace

for ( int i = 0 ; i < value.Count ; ++i )

with

foreach(Token item in value)

to eliminate the index operations value[ i ].

StackExchange Code Review Q#1495, answer score: 3