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Using bucket sort to rank students based on their marks

Submitted by: @import:stackexchange-codereview··
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rankstudentsusingbasedbucketsortmarkstheir

Problem

Problem:


n students have marks and names. Rank students based on their marks and print their names.

#include 
#include 

struct student
{
    int marks;
    char name[50];
};

struct listnode
{
    struct student * data;
    struct listnode *next;
};

addtofrontoflist(struct listnode *listhead,struct student *node)
{
    //make a block of listnode.
    struct listnode bucketnode;
    bucketnode.data=node;

    struct listnode *tmp;
    tmp=listhead->next;
    listhead->next=&bucketnode;
    bucketnode.next=tmp;
}

bucket_sort(struct student array[],int n)
{
    struct listnode *buckets[n]; 
    int i,j;
    struct listnode *temp;
    for(i=0;idata->marks,temp->data->name);
    }
}

main()
{
    struct student array[5]={"1,one","2,two","2,two","4,four","1,one"};
    bucket_sort(array,5);
}

Solution

-
Since your functions have no explicit return types (and surely you've compiled this), you must be implementing this under an older C standard that allowed for implicit return types.

Regardless, I would recommend adding explicit return types to your functions:

-
main() should return an int as it is supposed to return an integer value based on the program's execution outcome (either 0 for success or 1 for failure). However, if it will always execute successfully, then you can omit the return 0 at the end.

-
The other functions should return void as they're not already returning anything.

-
You may typedef your structs to avoid having to type struct elsewhere.

-
You're inconsistently using snake_case naming and all-lowercase. The latter is not very readable as compound words should be separated. Since you're already using snake_case, just use that for all of your variable and function naming here.

-
marks should probably just be mark as it's just a single variable. But if a student is supposed to have more than one, then marks should be an array. Also, must this be an integer type, or can a student have a decimal value as a mark? This would of course depend on how you want to implement this grading system.

-
The variable j declared in bucket_sort() is unused, so it should be removed. You should have your compiler warnings up high so that you'll be told when this occurs.

-
You should add whitespace between operators for readability. Keeping lines shorter would not be of much benefit as you should try not to have so much code on one line.

For instance, one of your for loops:

for(i=0;i<n;i++)


would look like this:

for (i = 0; i < n; i++)


And your array:

struct student array[5]={"1,one","2,two","2,two","4,four","1,one"};


should have its elements separated:

struct student array[5] = { "1,one", "2,two", "2,two", "4,four", "1,one" };


-
I'd recommend having a macro for the number of students:

#define NUM_STUDENTS 5


You can use this macro for the array size and anything else, and in case you'll ever need to change this number, this will be done in just one place.

In addition, bucket_sort() will no longer need to take a size.

student array[NUM_STUDENTS] = { "1,one","2,two","2,two","4,four","1,one" };
bucket_sort(array);

Code Snippets

for(i=0;i<n;i++)
for (i = 0; i < n; i++)
struct student array[5]={"1,one","2,two","2,two","4,four","1,one"};
struct student array[5] = { "1,one", "2,two", "2,two", "4,four", "1,one" };
#define NUM_STUDENTS 5

Context

StackExchange Code Review Q#2708, answer score: 11

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