Calculating sum of similarities of strings

Puzzle:


For two strings A and B, we define the similarity of the strings to be
the length of the longest prefix common to both strings. For example,
the similarity of strings "abc" and "abd" is 2, while the similarity
of strings "aaa" and "aaab" is 3. Calculate the sum of similarities of
a string S with each of its suffixes.


Explanation:


For ababaa the suffixes of the string are "ababaa", "babaa", "abaa",
"baa", "aa" and "a". The similarities of each of these strings with
the string "ababaa" are 6,0,3,0,1,1 respectively. Thus the answer is 6
+ 0 + 3 + 0 + 1 + 1 = 11.

How can I improve execution time of this (when larger testcases are provided)?

import java.util.Scanner;
public class Solution {
    public static void main(String[] args) {
        Scanner scanner;
        Solution sr = new Solution();
        scanner = new Scanner(System.in);
        int no_cases = scanner.nextInt();
        for (int i = no_cases; --i >=0; ) {
            String to_proc = scanner.next();
            sr.solve(to_proc);
        }
    }
    private void solve(String to_proc) {
            String str=to_proc;
            int len=to_proc.length();
            int count=0;
            int total=0;
            for(int i=1;i<len;i++)
            {
                count=0;
                for(int j=i;j<len;j++)
                {
               //     System.out.println(str.charAt(j)+" , "+str.charAt(j-i));
                    if(str.charAt(j-i)==str.charAt(j))
                    {
                        count++;
                    }
                    else
                    {
                        break;
                    }
                }
                total=total+count;
            }
            System.out.println(total+len);
    }
}

I think you need a suffix tree.

Its a data structure that puts all the prefixes of a string in a tree. This makes a number of operations faster, and I think you can make your similarity metric qualify.

StackExchange Code Review Q#7283, answer score: 5