Breadth and Depth First Search in Java

BFS and DFS in Java. Please give suggestions!!

Class Main {
    public void bfs()
    {
        // BFS uses Queue data structure
        Queue queue = new LinkedList();
        queue.add(this.rootNode);
        printNode(this.rootNode);
        rootNode.visited = true;
        while(!queue.isEmpty()) {
            Node node = (Node)queue.remove();
            Node child=null;
            while((child=getUnvisitedChildNode(node))!=null) {
                child.visited=true;
                printNode(child);
                queue.add(child);
            }
        }
        // Clear visited property of nodes
        clearNodes();
    }

    public void dfs() {
        // DFS uses Stack data structure
        Stack stack = new Stack();
        stack.push(this.rootNode);
        rootNode.visited=true;
        printNode(rootNode);
        while(!stack.isEmpty()) {
            Node node = (Node)s.peek();
            Node child = getUnvisitedChildNode(n);
            if(child != null) {
                child.visited = true;
                printNode(child);
                s.push(child);
            }
            else {
                s.pop();
            }
        }
        // Clear visited property of nodes
        clearNodes();
    }
}

Class Node {
   Char data;
   Public Node(char c) {
      this.data=c;
   }
}

There seem to be some inconsistencies here. What is s? I guess this is the stack? Also declaring a class Main is a little strange. You certainly want to have a main method, but a Main class?

Also I'd suggest you not use raw collections e.g. replace

Queue queue = new LinkedList();

with

Queue queue = new LinkedList();

You may like to consider implementing DFS recursively so that you don't have to explicitly use a stack, although that's a matter of taste. Also, where is getUnvisitedChildNode() defined? Where are the edges of the graph actually stored? This could be e.g. an adjacency list carried around by each node, or perhaps in another object, but it should be somewhere.

StackExchange Code Review Q#8896, answer score: 8