Guessing Game: computer generated number between 1 and 100 guessed by user

The required output is stated just before the main() function. Is there a better way to achieve it? I feel like I am repeating code unnecessarily but am unable to find a better way to get the result. Not squeezing the code too much, like one liners, but reasonably using better logic.

#!/usr/bin/env python
# -*- coding: utf-8 -*-

#Time to play a guessing game.

#Enter a number between 1 and 100: 62
#Too high. Try again: 32
#Too low. Try again: 51
#Too low. Try again: 56

#Congratulations! You got it in 4 guesses.

import random

def main():

    return 0

if __name__ == '__main__':
    main()

print("Time to play a guessing game.")

val = random.randint(1, 100)
guess = 0
count = 1

guess = input("\n\t\tEnter a number between 1 and 100: ")
guess = int(guess)

print("")
print("randint is", val)
print("")

if (guess == val):
    print("\nCongratulations! You got it in", count, "guesses.")

while(guess != val):

    if guess > val:
        print("Too high. Try again:", guess)
        guess = input("\n\t\tEnter a number between 1 and 100: ")
        guess = int(guess)
        count = count + 1
        if guess == val:
            print("\nCongratulations! You got it in", count, "guesses.")
            break

    elif guess < val:
        print("Too low. Try again:", guess)
        guess = input("\n\t\tEnter a number between 1 and 100: ")
        guess = int(guess)
        count = count + 1
        if guess == val:
            print("\nCongratulations! You got it in", count, "guesses.")
            break
    else:
        pass

print("")

• The pythonic way to do count = count + 1 is count += 1

-
You don't need to repeat the 'guess again' part of the game twice:

if guess > val:
    print("Too high. Try again:", guess)  
elif guess < val:
    print("Too low. Try again:", guess)
guess = int(input("\n\t\tEnter a number between 1 and 100: "))
count += 1
if guess == val:
    print("\nCongratulations! You got it in", count, "guesses.")
    break

-
You don't need to add the extra if statement because if guess != val, then the loop with break anyway:

while guess != val:
    if guess > val:
        print("Too high. Try again:", guess)  
    elif guess < val:
        print("Too low. Try again:", guess)
    guess = int(input("\n\t\tEnter a number between 1 and 100: "))
    count += 1
print("Congratulations! You got it in", count, "guesses.")

-
I think print("randint is", val) was probably for testing purposes, but it's still in your code!

-
If you execute your program outside the command module (I'm not quite sure what it's called), the program will close immediately after it's finished; it's always best to give the user the choice of when to quit, so insert this at the end of your code:

input("Press enter to quit")

-
The first section is unneeded:

def main():`, `if __name__ == "__main__":

-
The first if statement is also unneeded:

if guess == val:

-
You don't need to define guess = 0 the first time.

So, all in all, my improvement of your code is:

import random
print("Time to play a guessing game.")
val = random.randint(1, 100)
count = 1    
guess = int(input("\n\t\tEnter a number between 1 and 100: "))
while(guess != val):    
    if guess > val:
        print("Too high. Try again:", guess)    
    elif guess < val:
        print("Too low. Try again:", guess)
    guess = int(input("\n\t\tEnter a number between 1 and 100: "))
    count += 1
print("\nCongratulations! You got it in ", count, " guesses.")
input("Press enter to quit.")

StackExchange Code Review Q#23694, answer score: 10