smallest number divisible by all numbers from 1 to 20? Project Euler question 5

I'm currently working my way through the questions on Project Euler and I am on question 5. Is this the best possible solution? Any suggestions welcomed!

List divisors = new List{ 11, 12, 13, 14, 15, 16, 17, 18, 19, 20 };

        int n = 1;

        while (true)
        {
            n++;
            foreach (int d in divisors)
            {
                if (n % d != 0) { break; }
                if (d==20)
                {
                    Console.Write(n);
                    Console.ReadLine();
                }
            }             
        }

The most optimal solution would be to calculate the LCM of 1 to 20 directly using the standard Euclidean algorithm.

// calculate GCD using Euclidean algorithm
public long GCD(long a, long b) {
    if (b == 0)
        return a;
    else
        return GCD(b, a % b);
}

// calculate LCM using simple formula based on GCD
public long LCM(long a, long b) {
    var gcd = GCD(a, b);
    return a * b / gcd;
}

// iteratively calculate LCM of 1 through 20
public static void Main(string args[]) {
    long result = 1;

    // loop through each value 1 to 20, and LCM with previous result
    for (long n = 2; n <= 20; n++) {
        result = LCM(result, n);
    }

    // print out the result
    Console.WriteLine(result);
}

In terms of complexity, this algorithm is roughly O(n) for small n.

StackExchange Code Review Q#25200, answer score: 6