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Functions that converts day of year to month and day and reverse with error checking

Submitted by: @import:stackexchange-codereview··
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erroryearconvertsreversewithcheckingthatmonthandfunctions

Problem

There is no error checking in day_of_year or month_day. remedy this defect.

Here is the solution:

int day_of_year(unsigned int year, unsigned int month, int day) {
    int leap, i;

    leap = ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0));

    if(((month >= 1) && (month = 1) && (day = 1 && yearday = 1 && yearday  daytab[leap][i]; i++) {
          yearday -= daytab[leap][i];
        }
        *pday = yearday;
        *pmonth = i;
    }
    else {
        printf("error: the yearday is invalid");
    }
}


In the day_of_year's case I have to check if the yearday is a valide one. 1 <= yearday <= (365 || 366). I changed the parameters type to unsigned, because a day can't be negative nor a year.

In the month_day's case I check if the month is a valid one, it should be 1 <= month <= 12. After this, I check if the day belongs to a valid interval.

This exercise can be found in K&R2 at page 126.

Solution

-
Incorrect yearday limit

// if((leap == 1 ... || (leap == 0 && (yearday >= 1 && yearday = 1 && yearday <= 365))) {
//                                                             365


-
month_day() and day_of_year() should use consistent types for month. Suggest int for both.

// int day_of_year(unsigned int year, unsigned int month, int day) {
// void month_day(unsigned int year, unsigned int yearday, int *pmonth, int *pday) {
int day_of_year(unsigned int year,         int month, int day) {


-
month_day() and day_of_year() should use consistent types for yearday. Suggest int for both.

// int day_of_year(unsigned int year, unsigned int month, int day) {
// void month_day(unsigned int year, unsigned int yearday, int *pmonth, int *pday) {
int day_of_year(unsigned int year, int month, int day) {
void month_day(unsigned int year, int yearday, int *pmonth, int *pday) {


-
Leap year calculation leap = ((year... is good back to 1583. For years 4 to 1582 it is leap = (year % 4 == 0); 1582 has other complications. Before 4 has complications.

-
Suggest month_day() return int to indicate success or failure.

Code Snippets

// if((leap == 1 ... || (leap == 0 && (yearday >= 1 && yearday <= 366))) {
if((leap == 1 ... || (leap == 0 && (yearday >= 1 && yearday <= 365))) {
//                                                             365
// int day_of_year(unsigned int year, unsigned int month, int day) {
// void month_day(unsigned int year, unsigned int yearday, int *pmonth, int *pday) {
int day_of_year(unsigned int year,         int month, int day) {
// int day_of_year(unsigned int year, unsigned int month, int day) {
// void month_day(unsigned int year, unsigned int yearday, int *pmonth, int *pday) {
int day_of_year(unsigned int year, int month, int day) {
void month_day(unsigned int year, int yearday, int *pmonth, int *pday) {

Context

StackExchange Code Review Q#41343, answer score: 4

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