Bash script to clear files not matching a given extension

Using LaTeX creates a bunch of auxiliary files like foo.aux, foo.log, etc. Sometimes, I want to create a clean run of my document. I usually manually execute this in the terminal as

$ ls foo*
foo.tex
foo.aux
foo.log
foo.bbl
foo-blx.bib
$ rm foo{.aux,.log,.bbl,-blx.bib}

This works fine. However, it is error-prone and I don't want to accidentally erase my .tex file. So I added this function to my ~/.bashrc:

# Delete all non-TeX files
# invoke as: cleantex foo
# where: foo.tex, foo.aux, foo.log, etc. are files in directory
cleantex () {
    if [ -n "$1"]; then
        name = $(basename -s ".tex" "$1")
        rm -f $name{.!(*tex),-blx.bib}
    fi  
}

My question is about the key line

rm -f $name{.!(*tex),-blx.bib}

that actually executes the script.

Is this line well-written? What might I improve here?

My real concerns with the script are:

• cleantex path/to/file.tex will not delete files in that path, but in the current directory.

• you should check the actual .tex file exists before you delete all the things around it.

• the brace-expansion is unnecessarily complicated...... especially when combined with the extended glob !(*tex). I would manually resolve the brace-expansion so that there is only one complicated operation on that line.

• I would use actual glob-expansion and only delete existing files.... and not use the -f option on rm (which does more than just suppress the error message if files do not exist....)

StackExchange Code Review Q#45556, answer score: 6