Sample n items without replacement in Prolog

I have the following Prolog code which samples n items from a list without replacement:

samp(0,_,Sample,Sample).
samp(N,Domain0, Sample0, Sample):-
  N >= 0,              
  length(Domain0,L),
  RandomNumber is random(L),
  nth0(RandomNumber, Domain0, X),
  delete(Domain0,X,Domain1),
  append(Sample0,[X],Sample1),
  N1 is N-1,
  samp(N1,Domain1,Sample1,Sample).

sample(Domain,N,Sample):-
  samp(N,Domain,[],Sample).

Is there a 'nicer' way to do this?

In SWI-Prolog you could do this that way:

sample_swi(Domain, N, Sample) :-
    random_permutation(Domain, Permutation),
    length(Sample, N),
    append(Sample, _, Permutation).

Be careful, this predicate is not a true relation (just as in your code).

StackExchange Code Review Q#49471, answer score: 4