Find the maximum number of consecutive zeros in an array

Question: To find the maximum number of consecutive zeros in a given
array.


Example:


Input: \${1, 2, 0, 0, 2, 4, 0, 2, 0, 0, 0, 5, 0, 0, 0, 0, 0, 0, 7, 0}\$


Output: "Maximum number of consecutive zeros : 6"

Here is what I've come up with:

public class ZeroSeriesLength {

    public static void main(String[] args) {

        int[] values = {1, 2, 0, 0, 2, 4, 0, 2, 0, 0, 0, 5, 0, 0, 0, 0, 0, 0, 7, 0};

        int maxLength = 0;
        int tempLength = 0;

        for (int i = 0; i  maxLength) {
                maxLength = tempLength;
            }
        }

        System.out.println("Maximum number of consecutive zeros : " + maxLength);
    }
}

Is the logic correct? Or can it be done via a simple approach?

Just a few short comments on your code:

Separation of concerns:

You should separate functionality into different parts. Currently your main method does everything. For small applications like this, that may not be a problem, but as soon as you have larger applications, it becomes more and more unpractical.

You should thus extract your "logic" into a method:

private static int countSuccessiveZeros(int[] values) {
   int maxLength = 0;
   int tempLength = 0;
   //....
   // Looping here
   return maxLength;
}

Now if you wanted to not count zeros, but twos, you could simply modify the code to the following:

private static int countSuccessive(int[] values, int target) {
   int maxLength = 0;
   int tempLength = 0;
   //Your loop here, instead of 0 use target to compare
   return maxLength;
}

This also makes your main-method more readable:

public static void main(String[] args) {
   int[] values = {1, 2, 0, 0, 2, 4, 0, 2, 0, 0, 0, 5, 0, 0, 0, 0, 0, 0, 7, 0};
   int successiveZeros = countSuccessive(values, 0);
   System.out.println("Maximum number of consecutive zeros : " + successiveZeros);
}

Naming:

Very nice, a compliment. Your variable names are short, clear, descriptive and follow Java conventions (camelCase). Keep it up ;)

StackExchange Code Review Q#49610, answer score: 19