Printing inputted, largest, odd integer

The program asks the user to input 10 integers, and then prints the largest odd number that was entered. If no odd number was entered, it prints a message to that effect.

q = int(raw_input("Please enter an integer:"))
r = int(raw_input("Please enter another integer:"))
s = int(raw_input("Please enter another integer:"))
t = int(raw_input("Please enter another integer:"))
u = int(raw_input("Please enter another integer:"))
v = int(raw_input("Please enter another integer:"))
w = int(raw_input("Please enter another integer:"))
x = int(raw_input("Please enter another integer:"))
y = int(raw_input("Please enter another integer:"))
z = int(raw_input("Please enter one last integer:"))

odd = []
if q%2 != 0:
    odd += [q]
if r%2 != 0:
    odd += [r]
if s%2 != 0:
    odd += [s]
if t%2 != 0:
    odd += [t]
if u%2 != 0:
    odd += [u]
if v%2 != 0:
    odd += [v]
if w%2 != 0:
    odd += [w]
if x%2 != 0:
    odd += [x]
if y%2 != 0:
    odd += [y]
if z%2 != 0:
    odd += [z]
if q%2 == 0 and r%2 == 0 and s%2 == 0 and t%2 == 0 and u%2 == 0 and v%2 == 0 and w%2 == 0 and x%2 == 0 and y%2 == 0 and z%2 == 0:
    print "None of the values given are odd."
else:
    print max(odd), "is the largest odd number."

Use loops!

odd_nums = []
for i in xrange(10):
    value = int(raw_input('Enter an integer: '))
    if value % 2 != 0:
        odd_nums.append(value)

if len(odd_nums) != 0:
    print max(odd_nums)
else:
    print "No odd values"

How to read this line:

for i in xrange(10):

This line means starting at 0 (the default starting point for xrange()), and ending at 10-1 (upper bound is not included), execute the following code with i set to the current iteration of the loop. This executes the code exactly 10 times (i = 0, 1, 2, 3, 4, 5, 6, 7, 8, 9).

The rest was made as similar to your code as possible, and so should be understandable.

StackExchange Code Review Q#57410, answer score: 4