Squaring numbers in an array

I want to know if there is a better way to square numbers in an array. This is what I wrote:

#include 
using std::cout;
using std::endl;

void square(int []);

int main()
{
    int array[] = {2,4,6,8,10};

    square(array);
    for(auto i : array)
        cout << i << " ";

}

void square(int array[])
{
    int size = sizeof(array)/sizeof(array[0]);
    for(int i=0; i< size; i++)
        array[i] *= array[i];
}

-
int size = sizeof(array)/sizeof(array[0]);

Just so you know, sizeof() returns size_t.

-
You can use a vector instead of an array.

vector data = {2,4,6,8,10};

• Simplify squaring using std::transform() and use a lambda expression

in place of a function object:

#include 
#include 
#include 

using std::cout;
using std::transform;
using std::vector;

int main()
{

    vector data = {2,4,6,8,10};

    transform(data.begin(), data.end(), data.begin(), [](int x){return x*x;});

    for(auto i : data)
        cout << i << " ";

}

StackExchange Code Review Q#66594, answer score: 5