Javascript condition optimization

Can the following condition be optimized/simplified ?

if (!this.properties.width || 
    this.properties.width <= 0 || 
    !this.properties.height || 
    this.properties.height <= 0)
  return;

So basically if properties does not have a width or height property or the width or height property is less than or equal to zero then return

I'd simply flip it around:

if( !(this.properties.width > 0 && this.properties.height > 0) ) {
  return;
}

This will catch null, undefined, NaN, etc., etc.. It will allow numeric strings (provided they can be coerced to a number greater than zero), and of course it'll allow straight-up positive, non-zero numbers.

Update: There's one edge-case I've come across: Arrays. It's some unfortunate JavaScript weirdness to do with type coercion:

[] > 0;     // => false (so far so good)
[0] > 0;    // => false (as it should be)
[1] > 0;    // => true  (what?)
[1, 1] > 0; // => false (WHAT?)

So an array with just a single numeric element will be treated as a number when comparing.

Well, actually, as far as I can tell, the array is coerced to a string by coercing each element to a string, and joining them with a comma, and the joined string is then compared lexicographically coerced to a number in order to be compared. (Thanks to Robert in the comments for the correction)

[1] + 0;    // => "10"
[1, 1] + 0; // => "1,10"
"0" > 0;    // => false
"1" > 0;    // => true
"1,1" > 0;  // => false

I love JavaScript, but sometimes... jeez...

StackExchange Code Review Q#67432, answer score: 11