Regex for curly quotes and apostrophes

After years of fear and procrastination I decided to learn regular expressions. This is the result:

CoffeScript:

str = "#{chapter.title}\n\n#{chapter.content}\n\n"

str.replace(/>([^>]+)
  r.replace(/(>|\s)"/g, "$1“")
   .replace(/"/g, "”")
   .replace(/("|\s)'/g, "$1‘")
   .replace(/'/g, "’")
)

JavaScript:

var str = "" + chapter.title + "\n\n" + chapter.content + "\n\n";

str.replace(/>([^>]+)|\s)"/g, "$1“")
          .replace(/"/g, "”")
          .replace(/("|\s)'/g, "$1‘")
          .replace(/'/g, "’");
});

As you can see, the code turns all "straight" quotation characters (plus apostrophe) to “curly” ones. It was a bit hard because the input had stuff like this:

"Yes," he said, "I met her. She's very 'friendly.'"

So I had to make sure the quotes inside the HTML tags were not being included. And make the code know that quotations wouldn't always be preceded by a space (sometimes by an >).

I welcome any suggestion to make the code shorter, more efficient/readable.

Since you know that the double quotes will always be matched, you might try this instead of your first two replaces:

r.replace(/"([^"]*)"/g, "“$1”")

I think that's a little stronger. The unmatched single quotes are harder, and I think what you have is reasonable. I might try this tack though if JavaScript has the \w for word letters. (If not, use [a-zA-Z].)

.replace(/(\w)'(\w)/g, "$1’$2")
.replace(/'([^']*)'/g, "‘$1’")

StackExchange Code Review Q#75699, answer score: 3