Simple Hangman game

It randomly gets a word from an array of Strings. It prints out a '_' char for every letter of the word, displays the ones you have already guessed and displays the ones you have missed.

Some advice would be welcome, such as what I should change, avoid and so on.

Main class:

import java.util.Scanner;
public class Main {
public static void main(String[] args) {

    Game game = new Game();
    Scanner keyboard = new Scanner(System.in);
    String input;
    char guess;

    game.initializeGame();
    do {
        System.out.print("\n-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=\n\nWord: ");
        game.showRow();

        System.out.print("\n\nMisses: ");
        game.showMisses();

        System.out.print("\nGuess: ");
        input = keyboard.next();

        if (input.equalsIgnoreCase("exit"))
            break;
        else if (input.equalsIgnoreCase("new"))
            game.initializeGame();
        else {
            guess = input.charAt(0);
            game.checkRow(guess);

            if (game.isLooser()) {
                System.out
                        .println("\nGame Over!\nYou have missed 8 times!\nThe word was "
                                + game.getSecretWord()
                                + " ! \nThe game will now reset!\n");
                game.initializeGame();
            }

            else if (game.IsWinner()) {
                System.out
                        .println("\nCongratulations!\nYou have guessed the word!\nThe game will now reset!\n");
                game.initializeGame();
            }

        }

    } while (true);

    System.out.println("\nThank you for playing !");
    keyboard.close();
}

}

Game class

```
import java.util.Random;

public class Game {
Random random = new Random();
StringBuffer misses = new StringBuffer("");

private final String[] wordArray = { "baboons", "beavers", "cats",
"chickens", "choughs", "dolphins", "eagles", "elephants",
"flamingoes", "giraffes", "grasshoppers", "h

Remember that any function of the type

def function(arg):
    if condition(arg):
        return True
    return False

can be shortened to:

def function(arg):
    return condition(arg)

You can apply this advice to:

public boolean isLooser() {
    if (misses.length() / 2 > 7)
        return true;
    return false;
}

Also I think that you can simplify the condition to:

misses.length() > 14

The function:

public boolean IsWinner() {
    for (int i = 0; i < hangman.length; i++)
        if (hangman[i] == '_')
            return false;
    return true;
}

Can benefit from built-ins:

public boolean IsWinner() {
    return hangman.indexOf('_') == -1; // '_' never occurs
}

As well as this one:

private boolean isCharInWord(char guess) {
    return secretWord.indexOf(guess) != -1;
}

Brace yourself

Please always use braces, doing so increases readability and reduces stupid-bugs probability.

A bit of generality

setWord is specific to this game, I would do:

public void randomChoice(array) {
    return array[random.nextInt(array.length)];
}

and then in the initialization I would call:

public void initializeGame() {
   secretWord =  randomChoice(wordArray);
   // ...
}

I think my version is more immediate to understand.
(By the way, I can see that it is an array, so you can remove that from the name, a simple words would be better).

StackExchange Code Review Q#96351, answer score: 4