Using random to generate strings

I have code that reads from files of surnames, female and male names and randomly generates a name in the following format: lastname, male/female name.

The files are in the following format:


JAMES 3.318 4,840,833 1

I have the following working code:

def picks(filename):
    with open(filename) as f:
        lines = [line.strip('\n') for line in f]
        pick = randint(0, len(lines))
    return lines[pick].split()[0]

def random_name(number_of_names):
    nselect = ''
    for _ in range(1, number_of_names+1):
        g = randint(0,1)
        if g==1:
            nselect = picks('femalenames.txt')
        else:
            nselect = picks('malenames.txt')
        print(g)
        print( '{0:s}, {1:s}\n'.format(picks('surnames.txt'), nselect))

random_name(5)

The code generates the correct output but I feel the code could be trimmed a bit.

Your intuition was accurate! Here is a shortened version with (almost-)identical functionality:

from random import choice

def picks(filename):
    with open(filename) as f:
        lines = [line.strip() for line in f]
    return choice(lines).split()[0]    

def random_names(number_of_names):
    for _ in range(number_of_names):
        nselect = picks(choice(('femalenames.txt', 'malenames.txt')))
        print('{0:s}, {1:s}\n'.format(picks('surnames.txt'), nselect))

random_name(5)

Note the following:

• str.strip removes whitespace (including newlines) by default, so you don't need to make the argument explicit;

• random.choice is a neater way to select a random item from a list than generating and using an index;

• random_names is a better name for the function, as you can specify a varying number of names;

• You don't need to initialise nselect;

• Why carefully adjust an index you aren't actually using by one? 0 is the default start for range, so we can just use number_of_names directly; and

• Selecting directly from the two possible filenames makes the functionality more obvious (although you can no longer print(g), which was a bad name anyway).

StackExchange Code Review Q#98370, answer score: 5