Filtering out empty Optionals

I want to convert my list of optional strings to a list of strings by getting rid of the empty Optionals.

Is there a shorter version for achieving this than the following code (except statically importing the methods of Collectors)?

List> stringsMaybe = Arrays.asList(Optional.of("Hi"),
                                      Optional.empty(), Optional.of(" there!"));

List strings = stringsMaybe
            .stream()
            .filter(Optional::isPresent)
            .collect(Collectors.mapping(Optional::get, Collectors.toList()));

It's more idiomatic to use .map on the stream instead of Collectors.mapping:

stringsMaybe.stream()
    .filter(Optional::isPresent)
    .map(Optional::get)
    .collect(toList());

Without introducing a helper method or a custom collector, that's the shortest and clearest way to do this.

Since Java 9, Optional offers a stream method, enabling you to do .flatMap(Optional::stream) instead of .filter(...).map(...).

StackExchange Code Review Q#109294, answer score: 37