Top 5 most common words in Python

I would like to hear feedback from an interviewer's perspective on how to improve the following code:

from collections import Counter

def word_map(string):
    word_dict = {}
    stop_word_file=open("stopwords.txt", "r")
    stop_words =stop_word_file.read().split()
    for word in string.split():
        word = filter(str.isalnum, word).lower()
        word = word.strip()
        if word != '' and word not in stop_words:
            if word in word_dict.keys():
                word_dict[word] +=1
            else:
                word_dict[word] = 1

    return word_dict

file = open("story.txt", "r")

five_top_words = Counter(word_map(file.read())).most_common(5)
for letter, count in five_top_words:
    print '%s : %10d' %(letter, count)

I second @Dannnno arguments except for the fact that you don't need to split the work into tinier functions.

In fact I'd say quite the opposite as using more function let you turn them into generators for a more efficient memory usage.

You should also make yourself familiar with the str.format syntax which is the new way to go over the % formatting syntax.

My proposal is:

from collections import Counter
from itertools import chain

def word_map(filename, stop_words_file):
    with open(stop_words_file) as f:
        stop_words = set(f.read().split())

    with open(filename) as f:
        for line in f:
            words = (filter(str.isalnum, w).lower() for w in line.split())
            yield (w for w in words if w and w not in stop_words)

def top_words(filename, stopfile, count):
    words = chain.from_iterable(word_map(filename, stopfile))
    return Counter(words).most_common(count)

if __name__ == '__main__':
    for word, count in top_words('story.txt', 'stopwords.txt', 5):
        print '{} : {:>10}'.format(word, count)

StackExchange Code Review Q#129793, answer score: 4