Displaying all substrings of some given string

I solved exercise 8 from Core Java for Impatient, chapter 1. This exercise is to implement a displayAllCombinations method to display all substrings of the given string.

I would like to prove that following algorithm is valid in Java. I wonder if there is an easier solution?

package pl.hubot.exercises.corejava.r01.ex08;

import java.util.Scanner;

/**
 * This program contains mine solutions of exercises
 * from book Core Java for the Impatient, chapter 1.
 *
 * The content of following exercise:
 * "Write a program that reads a string and displays all contained
 * in it non-empty strings."
 *
 * @version 1.00 23-07-2016
 * @author Hubot
 */
public class Program
{
    public static void main(String[] args)
    {
        System.out.print("Enter any string: ");
        Scanner in = new Scanner(System.in);
        String text = in.nextLine();
        displayAllCombinations(text);
    }

    private static void displayAllCombinations(String text)
    {
        int offset = 0;
        int current = 0;
        int ending = text.length();
        while (offset != ending)
        {
            String result = text.substring(current, ending - offset);
            if (!result.equals(""))
                System.out.println(result);
            if (current != (ending - offset)) current++;
            else
            {
                current = 0;
                offset++;
            }
        }
    }
}

Sample run:

Enter any string: Amy
Amy
my
y
Am
m
A


The variable names offset, current, and ending could be better. offset seems to be distance from the end, and current acts as a starting index, so the names should reflect that.

The loop logic is cryptic. There is a current = 0; offset++; that "resets" the loop, so it would be more clearly written with nested for loops instead.

If you do it right, you shouldn't need to check !result.equals(""). If you did need to check, then it would be better written as !result.isEmpty().

private static void displayAllCombinations(String text) {
    for (int end = text.length(); end > 0; end--) {
        for (int start = 0; start < end; start++) {
            System.out.println(text.substring(start, end));
        }
    }
}

StackExchange Code Review Q#135693, answer score: 6