Simple Craps game

I'm trying to make my code smaller and less verbose.

The pass in the if statement are there because I need to check specifics on the dice roll.

The code is running a game of craps where on the first roll if I get a 7 or 11 I win, or if I get a 2,3,12 I lose. Any other number I keep rolling till I either get what I rolled the first time or I roll a 7. A return value of 1 means I won and 0 means I lost.

def craps():
    from random import randint
    dice = 0
    loop = 0
    while loop < 1:
        d1 = randint(1,6)
        d2 = randint(1,6)
        roll = d1 + d2
        dice += 1
        print(d1, d2)
        if dice == 1:
            first=roll
            if roll in {2,3,12}:
                loop += 1
                return 0
            elif roll in {7,11}:
                loop += 1
                return 1
            else:
                pass
        elif dice != 1:
            if first==roll:
                loop += 1
                return 1
            elif roll==7:
                loop += 1
                return 0
            else:
                pass
        else:
            pass

-
loop is totally useless. The loop doesn't have a chance to test it: as soon as it becomes 1, the function returns.

-
Don't test for special cases inside the loop. A first roll is special, so roll it before the loop begins (this also eliminates a dice variable).

-
Factor dice rolling into a function.

That said,

from random import randint

    def do_roll():
        return randint(1, 6) + randint(1, 6)

    def craps():
        first = do_roll()
        if first in {2,3,12}:
            return 0
        elif first in {7,11}:
            return 1

        while True:
            roll = do_roll()
            if roll == first:
                return 1
            elif roll == 7:
                return 0

StackExchange Code Review Q#145875, answer score: 5