Hash table using linear probing

This code is meant to implement a hash table class which uses linear probing.

I'm doing this to improve my style and to improve my knowledge of fundamental algorithms/data structures for an upcoming coding interview.

class Hash:
    def __init__(self):
        self.size = 11
        self.vals = [None] * self.size
        self.keys = [None] * self.size
        self.step = 1

    def put(self, key, val):
        ind = self.hash(key)

        if self.keys[ind] == None:
            self.keys[ind] = key
            self.vals[ind] = val

        elif self.keys[ind] == key:
            self.vals[ind] = val

        else:
            ind = self.rehash(ind)

            while (self.keys[ind] != None and 
                   self.keys[ind] != key):
                ind = self.rehash(ind)

            if self.keys[ind] == None:
                self.keys[ind] = key
                self.vals[ind] = val

            elif self.keys[ind] == key:
                self.vals[ind] = val

    def get(self, key):
        ind = self.hash(key)
        start_ind = ind
        val = None
        done = False

        while not done:
            if self.keys[ind] == key:
                val = self.vals[ind]
                done = True

            else:
                ind = self.rehash(ind)

                if ind == start_ind:
                    done = True

                elif self.keys[ind] == None:
                    done = True

        return val

    def hash(self, key):
        return key % self.size

    def rehash(self, oldhash):
        return (oldhash + self.step) % self.size

    def __getitem__(self, key):
        return self.get(key)

    def __setitem__(self, key, val):
        self.put(key, val)

break (or better yet return)

Instead of doing done = False/True. You could just use break and get rid of done altogether. But even better than that, just return.

This:

if self.keys[ind] == key:
            val = self.vals[ind]
            done = True

Becomes:

if self.keys[ind] == key:
            return self.vals[ind] # Value found!

This:

if ind == start_ind:
                done = True

            elif self.keys[ind] == None:
                done = True

Becomes:

if ind == start_ind: # Not found!
                return

            elif self.keys[ind] == None: # Not found!
                return

(You can return None if you want).

This gets rid of the val variable (and done)

StackExchange Code Review Q#147346, answer score: 2