My attempt at FizzBuzz (Python 3)

Is this a good solution for FizzBuzz? What can I do better?

for num in range(1, 101):
    if num % 3 == 0:
        if num % 5 == 0:
            print("FizzBuzz")
        else:
            print("Fizz")
    elif num % 5 == 0:
        print("Buzz")
    else:
        print(num)

It's a good attempt, it reads easily and I like that you nested the FizzBuzz check within Fizz branch.

This doesn't look like most of the code you see in the wild, though, so a good exercise would be to extract a function for the FizzBuzz logic that is independent from the loop over numbers.

def get_fizzbuzz(num:int) -> str:
    result = ""
    # fizzbuzz logic
    if num % 3 == 0:
        if num % 5 == 0:
            result = "FizzBuzz"
        # ...
    return result

You could even make it more flexible by optionally allowing different numbers to be entered instead of 3 and 5, while still using 3 and 5 as default values, like so:

def get_fizzbuzz(num:int, fizz:int = 3, buzz:int = 5) -> str:
    result = ""
    # fizzbuzz logic
    if num % fizz == 0:
        if num % buzz == 0:
            result = "FizzBuzz"
        # ...
    return result

Then you can just call the function in a loop using the default values:

for num in range(1, 101):
    print(get_fizzbuzz(num))

Or alternatively with different values for fizz and buzz:

for num in range(1, 101):
    print(get_fizzbuzz(num, 5, 7))

That will help you make your code more modular.

Note that I used Python 3's type hints in the function definition, which are completely optional but can make the code more clear, as well as provide static code analysis with certain tools.

StackExchange Code Review Q#149256, answer score: 4