patternpythonMinor
Minecraft server querier that generates an image of online players
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generatesimageminecraftplayersonlinethatserverquerier
Problem
This little chunk of code is run every 10 seconds on my desktop. It generates a PNG with up to 6 player faces based on the list of online players.
Is there any way for this code to execute faster? Any comments?
Each player has a PNG of their avatar's face with the title: "username_face.png" These are pasted into the main image when that player is online.
I wrote this script to compile their faces into a single image for display in a program called conky, allowing me to display the online players as part of my desktop.
```
from mcstatus import MinecraftServer
import os
from PIL import Image
#Query the server and get player names.
server = MinecraftServer("123.123.123.123", 25565)
query = server.query()
nameList = query.players.names
#Sort the list of player names.
nameList.sort()
#Open our temporary file for storing player names.
tempFile = open('server1_previous_players.txt', 'r')
oldNameList = tempFile.read().splitlines()
tempFile.close()
def createImage(players):
#create a blank transparent image with the dimensions: 212x147px.
baseImage = Image.new("RGBA", (212, 147))
slotList = [(17, 17), (82, 17), (147, 17), (17, 82), (82, 82), (147, 82)]
if len(players) > 0:
for x in range(0, 6):
try:
face = Image.open(str(nameList[x]).lower() + "_face.png", 'r')
baseImage.paste(face, slotList[x])
except:
break
baseImage.save("server1_online.png")
#If nothing changed, pass!
if nameList == oldNameList:
print("same thing!")
pass
#Else, if no-one is on, but the text file says people are on, empty the text file.
elif len(nameList) == 0 and len(oldNameList) > 0:
print("everyone left :'(")
tempFile = open('server1_previous_players.txt', 'w')
createImage(nameList)
#Else, if at least 1 person is on, generate a new image accordingly.
elif len(nameList) > 0:
tempFile = open('server1_previous_players.txt', 'w')
print('\n'.join(nameList), file=tempF
Is there any way for this code to execute faster? Any comments?
Each player has a PNG of their avatar's face with the title: "username_face.png" These are pasted into the main image when that player is online.
I wrote this script to compile their faces into a single image for display in a program called conky, allowing me to display the online players as part of my desktop.
```
from mcstatus import MinecraftServer
import os
from PIL import Image
#Query the server and get player names.
server = MinecraftServer("123.123.123.123", 25565)
query = server.query()
nameList = query.players.names
#Sort the list of player names.
nameList.sort()
#Open our temporary file for storing player names.
tempFile = open('server1_previous_players.txt', 'r')
oldNameList = tempFile.read().splitlines()
tempFile.close()
def createImage(players):
#create a blank transparent image with the dimensions: 212x147px.
baseImage = Image.new("RGBA", (212, 147))
slotList = [(17, 17), (82, 17), (147, 17), (17, 82), (82, 82), (147, 82)]
if len(players) > 0:
for x in range(0, 6):
try:
face = Image.open(str(nameList[x]).lower() + "_face.png", 'r')
baseImage.paste(face, slotList[x])
except:
break
baseImage.save("server1_online.png")
#If nothing changed, pass!
if nameList == oldNameList:
print("same thing!")
pass
#Else, if no-one is on, but the text file says people are on, empty the text file.
elif len(nameList) == 0 and len(oldNameList) > 0:
print("everyone left :'(")
tempFile = open('server1_previous_players.txt', 'w')
createImage(nameList)
#Else, if at least 1 person is on, generate a new image accordingly.
elif len(nameList) > 0:
tempFile = open('server1_previous_players.txt', 'w')
print('\n'.join(nameList), file=tempF
Solution
Maybe it will not increase the performance, but I have some general tips:
Use
I have rewritten the
If you prefer
Read more about
You need to close the files you open:
An
If you want to create an empty / transparent image when nobody is on, you can combine both
Use
while loops instead of for-loops with break. It will make your code more readable.I have rewritten the
createImage function for you:def createImage(players):
# create a blank transparent image with the dimensions: 212x147px.
baseImage = Image.new("RGBA", (212, 147))
slotList = [(17, 17), (82, 17), (147, 17), (17, 82), (82, 82), (147, 82)]
x = 0
while x < len(players) and x < 6:
face = Image.open(str(players[x]).lower() + "_face.png", 'r')
baseImage.paste(face, slotList[x])
x += 1
baseImage.save("server1_online.png")If you prefer
for over while, you can use:def createImage(players):
# create a blank transparent image with the dimensions: 212x147px.
baseImage = Image.new("RGBA", (212, 147))
slotList = [(17, 17), (82, 17), (147, 17), (17, 82), (82, 82), (147, 82)]
for slot, player in zip(slotList, players):
face = Image.open(str(player).lower() + "_face.png", 'r')
baseImage.paste(face, slot)
baseImage.save("server1_online.png")Read more about
zip hereYou need to close the files you open:
# If nothing changed, pass!
if nameList == oldNameList:
print("same thing!")
# Else, if no-one is on, but the text file says people are on, empty the text file.
elif len(nameList) == 0 and len(oldNameList) > 0:
print("everyone left :'(")
tempFile = open('server1_previous_players.txt', 'w')
tempFile.write("")
tempFile.close()
createImage(nameList)
# Else, if at least 1 person is on, generate a new image accordingly.
elif len(nameList) > 0:
tempFile = open('server1_previous_players.txt', 'w')
# write should be used instead of print
tempFile.write('\n'.join(nameList))
tempFile.close()
createImage(nameList)An
if-statement can be used without an else, so if there is only pass in there you don't need it.If you want to create an empty / transparent image when nobody is on, you can combine both
elif-statements:# If nothing changed, pass!
if nameList == oldNameList:
print("same thing!")
# else generate image and write new player list to file
else:
if len(nameList) == 0 and len(oldNameList) > 0:
print("everybody left")
tempFile = open('server1_previous_players.txt', 'w')
tempFile.write('\n'.join(nameList)) # writes "" for an empty player list
tempFile.close()
createImage(nameList)Code Snippets
def createImage(players):
# create a blank transparent image with the dimensions: 212x147px.
baseImage = Image.new("RGBA", (212, 147))
slotList = [(17, 17), (82, 17), (147, 17), (17, 82), (82, 82), (147, 82)]
x = 0
while x < len(players) and x < 6:
face = Image.open(str(players[x]).lower() + "_face.png", 'r')
baseImage.paste(face, slotList[x])
x += 1
baseImage.save("server1_online.png")def createImage(players):
# create a blank transparent image with the dimensions: 212x147px.
baseImage = Image.new("RGBA", (212, 147))
slotList = [(17, 17), (82, 17), (147, 17), (17, 82), (82, 82), (147, 82)]
for slot, player in zip(slotList, players):
face = Image.open(str(player).lower() + "_face.png", 'r')
baseImage.paste(face, slot)
baseImage.save("server1_online.png")# If nothing changed, pass!
if nameList == oldNameList:
print("same thing!")
# Else, if no-one is on, but the text file says people are on, empty the text file.
elif len(nameList) == 0 and len(oldNameList) > 0:
print("everyone left :'(")
tempFile = open('server1_previous_players.txt', 'w')
tempFile.write("")
tempFile.close()
createImage(nameList)
# Else, if at least 1 person is on, generate a new image accordingly.
elif len(nameList) > 0:
tempFile = open('server1_previous_players.txt', 'w')
# write should be used instead of print
tempFile.write('\n'.join(nameList))
tempFile.close()
createImage(nameList)# If nothing changed, pass!
if nameList == oldNameList:
print("same thing!")
# else generate image and write new player list to file
else:
if len(nameList) == 0 and len(oldNameList) > 0:
print("everybody left")
tempFile = open('server1_previous_players.txt', 'w')
tempFile.write('\n'.join(nameList)) # writes "" for an empty player list
tempFile.close()
createImage(nameList)Context
StackExchange Code Review Q#153728, answer score: 3
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